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5x^2+24x-324=0
a = 5; b = 24; c = -324;
Δ = b2-4ac
Δ = 242-4·5·(-324)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-84}{2*5}=\frac{-108}{10} =-10+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+84}{2*5}=\frac{60}{10} =6 $
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